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1. ÅÂºí¸´29(29,000¿ø) +2,900¿ø + 2,080¿ø + 130¿ø - 12,650¿ø = ¾à 21,460¿ø
1-2. ÅÂºí¸´29Ç÷¯½º(+55°è¿ÀÌ»ó¿ä±ÝÁ¦°áÇÕ) 29,000¿ø +2,900¿ø + 1,000¿ø + 60¿ø - 12,650¿ø - 3.000¿ø = ¾à 17,310¿ø
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À§¾à±Ý = ÃÑ ÇÒÀιÞÀº ±Ý¾× *[(1-¾àÁ¤»ç¿ëÀϼö/ÃѾàÁ¤Àϼö)] ´Ü,ÀϽÃÁ¤ ¹× ÀÌ¿ëÁ¤Áö´Â »ç¿ëÀϼö¿¡¼ Á¦¿Ü
¿¹) 29¿ä±ÝÁ¦·Î 1³â »ç¿ë½Ã À§¾à±Ý =>> 151,800¿ø *[1-(365/730)] = ¾à75,900¿ø <<´Ü,ÅÂºí¸´Ç÷¯½º½Ã À§¾à±ÝÃß°¡¹ß»ý<br />
Áï½¼ [ÅÂºí¸´29Ç÷¯½º]·Î [ÅÂºí¸´29]º¸´Ù 3,000¿ø ÇÒÀÎµÈ °¡°ÝÀ̳ª 24°³¿ù ¾àÁ¤À» ¾î±æ ½Ã Ç÷¯½º·Î À̵溻 ±Ý¾× ¸ðµÎ¸¦ ÅäÇؾßÇմϱî?
¾Æ´Ï¸é ³²ÀºÀÏ ¼ö¸¸ ÅÂºí¸´29 À§¾à±Ý ±×´ë·Î ³»´Â°ÇÁö¿ä?
1³â ÈÄ ÇØÁö ½Ã
À§¾à±Ý ´ë·« 100,000¿ø À̶ó Çϴµ¥ ±× µ¿¾È [ÅÂºí¸´29Ç÷¯½º]·Î ¿ù 17,310¿ø Çß´Ù¸é 1³â°£ [ÅÂºí¸´29Ç÷¯½º] ¿Í [ÅÂºí¸´29]ÀÇ
Â÷ÀÍ ¿ù3,000¿øµµ ¸ù¶¥ ÅäÇ϶ó´Â ¸»¾¸ÀαÁ¼î?
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